bash script to remove modules from httpd.conf that are not actually installed

confmodules=`cat /etc/httpd/conf/httpd.conf |grep -v ^#|grep  "modules/"|awk '{print $3}'|cut -d "/" -f 2`

for module in $confmodules; do
  echo "module=$module"
  if [ ! -f /etc/httpd/modules/$module ]; then
    linenum=`awk /"$module/{ print NR; exit}" /etc/httpd/conf/httpd.conf`
    sed -i "$linenum"s/.*// /etc/httpd/conf/httpd.conf
    echo "hey we don't have this $module in /etc/httpd/modules"
  fi
done

Basically the script checks all of the modules your httpd.conf tries to load.  Then it checks if the file actually exists in /etc/httpd/modules/ and if it doesn't it edits httpd.conf by removing the relevant line for the module that doesn't exist.


Tags:

bash, modules, httpd, conf, installedconfmodules, etc, grep, quot, awk, module, confmodules, echo, linenum, nr, sed, fi, doesn, edits, removing, relevant,

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