bash how to read a single line or filenames with spaces solution


This happens all the time, you are reading from a textfile which has spaces eg:

datainfo 00
datainfo 11

If you do loop on it like this:
for info in `cat $file`; do
echo "info=$info"
done


It will treat datainfo and 00 as two separate lines:

info=datainfo
info=00

Obviously that's not what we want and there are many weird solutions in bash but I'll try and pick what I feel is the simplest and most practical.

My favorite solution:

The key is setting the IFS as below and changing the default delimiter from space ""to newline or \n. You can use the same code and it tells bash to understand not to see a " " space as a delimiter so only a newline is counted. In plain English this makes it so files and directories with spaces are interpreted as intended.

IFS=$(echo -en "\n\b")

for info in `cat $file`; do
echo "info=$info"
done

Solution #2
while read -r; do
line=$REPLY
id=`echo $line|cut -f 2 -d " "`
ip=`echo $line|cut -f 1 -d " "`
done < migratelist.txt


Tags:

bash, filenames, spaces, textfile, eg, datainfo, info, echo, quot, solutions, ll, simplest, ifs, default, delimiter, newline, counted, directories, interpreted, en, reply, ip, migratelist, txt,

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