bash how to read a single line or filenames with spaces solution


This happens all the time, you are reading from a textfile which has spaces eg:

datainfo 00
datainfo 11

If you do loop on it like this:
for info in `cat $file`; do
  echo "info=$info"
done


It will treat datainfo and 00 as two separate lines:

info=datainfo
info=00

Obviously that's not what we want and there are many weird solutions in bash but I'll try and pick what I feel is the simplest and most practical.

My favorite solution:

The key is setting the IFS as below and changing the default delimiter from space " " to newline or \n. You can use the same code and it tells bash to understand not to see a " " space as a delimiter so only a newline is counted.   In plain English this makes it so files and directories with spaces are interpreted as intended.

IFS=$(echo -en "\n\b")

for info in `cat $file`; do
  echo "info=$info"
done

 

Solution #2
while read -r; do
  line=$REPLY
  id=`echo $line|cut -f 2 -d " "`
  ip=`echo $line|cut -f 1 -d " "`
done < migratelist.txt


Tags:

bash, filenames, spaces, textfile, eg, datainfo, info, echo, quot, solutions, ll, simplest, ifs, default, delimiter, newline, counted, directories, interpreted, en, reply, ip, migratelist, txt,

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